Sorry, bit of a newbie question here, I'll try an be as clear as I can

   (1&o. * 2&o.) d. 1
(2&o. * 2&o.) + 1&o. * -@(1&o.)   NB.  Great, no problems so far

   sincos =. (1&o. * 2&o.)
   sincos d. 1
sincos d.1              NB.  Hm....

What can I do to the "sincos" verb so that it is presented to the d.
adverb in terms of its primitives so that the differentiation can take
place?

   





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