Does this work? (untested) 
 datenum"1 aa 

Птн, 26 Ноя 2010, PackRat писал(а):
> I could never keep straight the various formats and datatypes the 
> getdate, todate, and todayno routines use, and so nine months ago I 
> wrote myself the following little utility for converting dates in any 
> of the various formats I use to the equivalent day number.  It seems to 
> work fine for single dates.  More recently I've had the need to feed it 
> a list of dates (one of the columns of an array).  However, after 
> spending all afternoon and evening at it, I just cannot seem to figure 
> out how to handle the simultaneous calculation for all elements of the 
> array list or column (implicit loop).  Rather than picking characters 
> out of the date string for each date, it picks rows once instead.  I 
> tried all sorts of things, to no avail.
> 
> ----------------------------------------------------------
> load 'dates'
> 
> date2num=: 3 : 0
>   if. 0=(+/ ' ,-/:' e. y) do.
>     y2=. ((i.4) { y),' ',(4 5 { y),' ',(6 7 { y)
>   else.
>     y2=. y
>   end.
>   todayno getdate y2
> :
>   todayno (1 getdate y)
> )
> 
> datenum '20080101'   <-- works
> 
> aa=. > 
> '20080101';'20080102';'20080103';'20080104';'20080105';'20080106';'20080
> 107';'20080109';'20080110'
> 
> datenum aa   <-- does NOT work  (this is what I'd like to do)
> 
> ----------------------------------------------------------
> 
> Can anyone help?  (Explicit only, no tacit, please.)  Thanks!
> 
> Harvey
> 
> ----------------------------------------------------------------------
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