[1] The "London Gold Fix" plot demo I mentioned previously has the line:
bgn=. todayno 2004,.(1+i.12),.1 I'd like to change the 2004 to something like (2004+i.3) so that a plot could handle multiple years rather than just one. Although that's the intuitive approach a beginner like me would take, it doesn't work that way. (The problem, of course, is that "stitch" can take a list and an atom, but it can't take two lists where each value of the one list is repeated as a fill for each value of the other list.) How can I adjust that line to get an output like this: 2004 1 1 2004 2 1 2004 3 1 . . . 2004 12 1 2005 1 1 2005 2 1 2005 3 1 . . . 2005 12 1 2006 1 1 2006 2 1 2006 3 1 . . . 2006 12 1 [2] Additionally, just as a matter of interest, how would one write a more complete "calendrical odometer"? In other words, all three elements (year, month, day) cycle through their values. (Leap years present problems, though.) The result would look like: 2004 1 1 2004 1 2 . . . 2004 1 31 2004 2 1 2004 2 2 . . . 2004 12 31 2005 1 1 2005 1 2 . . . 2006 12 31 (I suppose one could "cheat" by doing the calculation backwards--that is, going from a sequence of day numbers to the equivalent yyyy mm dd values.) [3] More challenging (I presume), how would one create such an odometer using any starting and ending dates in the format yyyy mm dd? I presume this might possibly be a multiline explicit verb (no tacit, please). (Again, I suppose one could "cheat", as above.) I really do appreciate the help you all give--thanks! Harvey ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
