Justin Paston-Cooper asked:
> The problem is to find the smallest positive number
> divisible by all of the numbers from 1 to 20.
> Could anyone tell me how to get around this with my current
> solution? How about some smarter solutions?
I haven't studied your current solution, but the "direct solution" is to
just ask for the least common multiple (LCM):
*./ >: i. 10
2520
*./ >: i. 20
232792560
-Dan
PS: Encountering a new expression like *./ (which I've never used outside
boolean lists before) refreshes my appreciation of J's design; it's so close
to */ which is the "obvious" common multiple of the vector.
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