On Mon, Mar 28, 2011 at 5:01 AM, Adrian May
<[email protected]> wrote:
> I don't understand what's happening here. Please help. Isn't there something
> out of the box for this?

Note that, personally, I do not know what you are trying to accomplish.

However if you are trying to build a list where each element is double
that of the previous element, you might use something like:

   2^1+i.4
2 4 8 16

If you are trying to accomplish something different you should of
course use a different approach.

-- 
Raul
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