Steven Taylor-3 wrote:
>
> Hi,
>
> as an exercise, I decided to make a simple "like" operator
>
> like=:([:*./([=])+.('?'E.]))
> NB. in english: get membership flags where '?' is in the set y
> NB. OR that with the comparison flags
> NB. *./ insert-AND to get the result
>
> the problem with this "like" operator is that x and y portions must be the
> same length. For example:
> 'abcaabc' like 'abc?abc'
> 1
> 'Abcaabc' like 'abc?abc'
> 0
> 'abcaabc' like 'abc?ab'
> |length error --- NB. fair enough that's how equals '=' is defined
>
> Is there an easy way to do guard conditionally, but to do this tacitly?
> i.e.
> the lengths are different, so return fail/zero?
> [...]
>
like=:([:*./([=])+.('?'E.]))
First shorter and cuter version (parenthesis removed):
like1 =: [: *./ = +. '?' E. ]
Then:
like2 =: 0:`([: *./ = +. '?' E. ])@.(=&#)
'abcabc' like2 'abc?bc'
1
'abcabc' like2 'abc?bcc'
0
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