0 and 2p1 are the same point on the unit circle.  This is related to Nyquist
sampling frequency if my memory still serves me.

Птн, 15 Июл 2011, mijj писал(а):
> in the original:
> NB.  We'll sample a sine wave at 194.18 Hz over 1 second.
> NB.  Or in other words: our x axis covers 194.18 radians,
> NB.  and we'll choose our 8000 sample points from that range:
> 
> that's 8000 sample *points*
> 
> 8000 sample points means 7999 sample *intervals*
> 
> ie. the range of (194.18 * 2p1 ) has
> 7999 sample intervals and 8000 sample points
> 
> so, in terms of proportion of a segment:
> 7999 intervals and 8000 points:
> (i. % <:) 8000   NB. ranges from 0 .. 1
> 
> so ...
> 
> SamplePoints =. 1 o. (194.18 * 2p1 ) * (i. % <:) 8000
> 
> 
> 
> On 2011-07-15 03:09, [email protected] wrote:
> > mijj>   yeh .. i always confuse samples with sample intervals too ..
> > mijj>   should be ...
> > mijj>   x =. 1 o. (194.18 * 2p1 ) * (i. %<:) 8000
> >
> > Should be not.  So, once more:
> >
> > The sample interval here is 1r8000 sec (=8kHz
> > sampling).  For Ian, the one-second signal is "194.14 sine waves",
> > and for direct treatment of "sin(x)" function with 1&o., the "x"
> > values ("points where the samples are taken") for the periods have
> > to be measured in the radians:
> >
> >     x =. (194.18 * 2p1 ) * (i. %<:) 8000
> >
> > At every sample point, the sample value ("sample") will be the
> > sine value or some scaling thereof:
> >
> >     samples =.  ...   1 o. x
> >
> > Less confused now?
> >
> >                                             Martin Neitzel
> >
> > (Before submitting my code last night, I checked a 440 Hz version
> > against my tuning fork.  You might get one before posting, too.)
> > ----------------------------------------------------------------------
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> >
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm

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