On Tue, Aug 9, 2011 at 4:49 PM, I wrote: > (([ = ] +/@#~ 0 = |~) i.&.<:)
As Ric Sherlock points out, you might not need that &.<: All it's doing is eliminating a 0 from the sum. Thus: (([ = ] +/@#~ 0 = |~) i.) That said, with this change, 0 is treated as a perfect number where before it was not. -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
