Your solution seems APLish, J got dyad -.
' '-.~":>:i.20
Птн, 09 Сен 2011, Don Guinn писал(а):
> You probably saw the method of boxing each number achieves what you are
> looking for. A different approach you might prefer is to let format (":)
> separate the numbers with blanks then remove the blanks.
>
> (]#~' '&~:)":>:i.20
> 1234567891011121314151617181920
>
> I think that the limit on the length of this operation is the same as the
> largest list allowed. I don't know what that limit is, but probably large
> enough to not be a problem.
>
> On Fri, Sep 9, 2011 at 5:17 AM, Lippu Esa <[email protected]> wrote:
>
> > Hi!
> >
> > You could use reqular expressions:
> >
> > require 'regex'
> > ('\B';' ')rxrplc ":>:i.20 NB. \B = Match except at a word boundary
> > 1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 2 0
> >
> > BR,
> >
> > Esa
> >
> > -----Original Message-----
> > From: [email protected] [mailto:
> > [email protected]] On Behalf Of David Vaughan
> > Sent: Thursday, September 08, 2011 6:42 PM
> > To: [email protected]
> > Subject: [Jprogramming] Turn list into string
> >
> > Hi,
> >
> > I want to turn a list of integers into string. I've tried this:
> >
> > 1":>:i.20
> > 123456789***********
> >
> > But I want it to look like: 1234567891011121314151617181920
> >
> > Also, I was wondering what the limit might be for how long this string is.
> >
> > Alternatively (preferably actually), I'd like to retain the list but with
> > each element being one digit in length. For example, 18 is split into 1 8.
> >
> > So for >:i.20 I'd want: 1 2 3 4 5 6 7 8 9 1 0 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1
> > 8 1 9 2 0
> >
> > Thanks.
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> >
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--
regards,
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