[x] i.&1@:condition list
0.5 i.&1@:< 0 0.2 0.5 0.6 0.9 0 0.6
3
Backed by special code if the condition is simple, as above
Henry Rich
On 9/25/2011 7:14 PM, David Vaughan wrote:
> Thanks, that seems quicker.
>
> I have another question, which is how can i find the first value that appears
> in the list that meets some condition - i.e. if the item> 0.5 - and return
> its position?
>
> On 25 Sep 2011, at 22:03, Henry Rich wrote:
>
>> (% 4 *>:@i.@#) _4 {:\ +/\ 1&p: 3 5 7 9 13 17 21 25 31 37 43 49
>> 0.75 0.625 0.666667
>>
>>
>> Henry Rich
>>
>> On 9/25/2011 4:46 PM, Don Guinn wrote:
>>> Apply the 1&p: to the list before doing the infixes. Cuts down the number of
>>> times 1&p: is invoked. But why are you adding one to the number of items in
>>> each infix? Seems like the 3 5 7 9 should give 0.75, not 0.6 .
>>>
>>> ((+/%#)&,)\_4,\1 p:3 5 7 9 13 17 21 25 31 37 43 49
>>>
>>> On Sun, Sep 25, 2011 at 1:47 PM, David Vaughan<[email protected]
>>>> wrote:
>>>
>>>> I've done: verb&,\
>>>>
>>>> I arranged the list to be of shape 'x 4'. This seems to work. The problem
>>>> I'm now having is that my verb is slow. Can this be refined
>>>> (significantly)?
>>>>
>>>> +/@:(1&p:) % 1&+@:#
>>>>
>>>> It takes finds the percentage of items in the list which are prime.
>>>>
>>>> On 25 Sep 2011, at 20:04, Don Guinn wrote:
>>>>
>>>>> verb=.<
>>>>> (verb&,)\_4,\3 5 7 9 13 17 21 25 31 37 43 49
>>>>> +-------+-------------------+-------------------------------+
>>>>> |3 5 7 9|3 5 7 9 13 17 21 25|3 5 7 9 13 17 21 25 31 37 43 49|
>>>>> +-------+-------------------+-------------------------------+
>>>>>
>>>>>
>>>>> On Sun, Sep 25, 2011 at 12:44 PM, David Vaughan<
>>>>> [email protected]> wrote:
>>>>>
>>>>>> I'm trying to apply a verb to infixes of length 4 but I want it to be
>>>>>> cumulative. i.e. in the list:
>>>>>>
>>>>>> 3 5 7 9 13 17 21 25 31 37 43 49
>>>>>>
>>>>>> I want:
>>>>>>
>>>>>> verb 3 5 7 9
>>>>>> verb 3 5 7 9 13 17 21 25
>>>>>> verb 3 5 7 9 13 17 21 25 31 37 43 49
>>>>>>
>>>>>> Any help? Thanks.
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