Period and colon are inflections when they are added to a word without space. They are then part of the preceding word. When preceded by a space, they start a new word.
Henry Rich On 9/29/2011 6:12 PM, Linda Alvord wrote: > Here is the space that is bothering me. The different results are dependent > upon the space before the colon. > > d=: 13 : '/:~ :/:@":&.>y' > d a,b > ------T-----┐ > │01123│01123│ > L-----+------ > > e=: 13 : '/:~:/:@":&.>y' > e a,b > 0 1 > > > -----Original Message----- > From: [email protected] > [mailto:[email protected]] On Behalf Of David Mitchell > Sent: Thursday, September 29, 2011 6:24 AM > To: Programming forum > Subject: Re: [Jprogramming] Permutations > > I find this helpful to see differences: > > /:~ :/:@":&.>a,b > -- ~ --- /: > -- : -+- /: > -- @ -+- ": > --&. -+-> > │ > --+ -- a > L------+- , > L- b > > > /:~:([:/:": )&.>a,b > -- /: > │ -- ~: > │ │ -- [: > --+ │ ----+- /: > │ +-&. -+ L- ": > L----+ L-> > │ > │ -- a > L------+- , > L- b > > -- > David Mitchell > > On 9/29/2011 5:45, Linda Alvord wrote: >> The only difference between the correct and the incorrect result is a > space >> before the second : . Should a space make a difference ever? In the >> correct result I can't understand what it is, what it does and why it does >> it. >> >> /:~ :/:@":&.>a,b >> ------T-----┐ >> │01123│01123│ >> L-----+------ >> >> >> /:~:([:/:": )&.>a,b >> 0 1 >> >> Since I set out originally to remove "atop", how can I do it? >> >> /:~ :([: /: ":)&.>a,b >> ------T-----┐ >> │10123│32110│ >> L-----+------ >> >> Hope you can help. Thanks. Linda >> >> -----Original Message----- >> From: [email protected] >> [mailto:[email protected]] On Behalf Of Ian Clark >> Sent: Thursday, September 22, 2011 9:13 PM >> To: Programming forum >> Subject: Re: [Jprogramming] Permutations >> >> Off-the-cuff... >> >> a=: 10123 >> b=: 32110 >> c=: 32100 >> -:/ /:~ :/:@":&.> a,b >> 1 >> -:/ /:~ :/:@":&.> a,c >> 0 >> >> >> On Thu, Sep 22, 2011 at 10:41 PM, David Vaughan >> <[email protected]> wrote: >>> Hi, what is the best (fastest) way to check whether a number is a >> permutation of another number? >>> I've tried listing all permutations of one number and checking whether > the >> other number is in the list of permutations. This seems pretty slow, so I >> was hoping for a faster method. >>> >>> Thanks. >>> ---------------------------------------------------------------------- >>> For information about J forums see http://www.jsoftware.com/forums.htm >>> >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm >> >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
