I suspect that "if the voltage reference is changed, the current is unaffected" means that if you change the arbitrary value assigned to ground (usually set to 0 Volts) it will not affect the curent.
-EdK Ed Keith [email protected] Blog: edkeith.blogspot.com ________________________________ From: Binayak Banerjee <[email protected]> To: [email protected] Sent: Tuesday, October 4, 2011 1:38 PM Subject: [Jprogramming] Basic Question about the J Circuit Analysis Lab Hi, I started looking at the Circuit Analysis lab that was included in the J Software release. However, I'm having a problem understanding the basic axioms underlying the treatment.. 1. The first axiom is that the algebraic sum of the currents flowing into and out of a "terminal" is 0. I take this as Kirchoff's current law, and have no issue with this. 2. The second axiom states that if the voltage reference is changed, the current is unaffected. <-- This I don't follow. The lab later states that "voltage vectors which differ by a scalar map to the same current". Again, I'm not sure I follow. Given a simple circuit consisting of a resistor, I get (from Ohm's law): V = IR. or when V is a function of I, V = f(I). Now, if I replace the (say) 10ohm reistor with a 5 ohm one, the same current maps to twice the voltage. Any clarification would be greatly appreciated. I tried sending mail directly to the author of the lab, but the mail bounced. Regards, Binayak ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
