On Wed, Oct 12, 2011 at 1:55 PM, David Vaughan <purpleblue...@googlemail.com> wrote: > Can anyone help explain how this works? Specifically (#,<./)/.
The phrase x F/. y uses x to classify items of y. Every item with the same x value gets grouped together in a list. F is given that list to evaluate. In this case, F is (#, <./) In other words, it produces two values: the length of its argument, and the smallest value in its argument. The results of all of the individual applications of F are assembled in the result you see. In this case, x was (/:~@":"0) 3^~i.10x In other words: you are grouping the elements of y (y being 3^~i.10x) by the digits used to represent those values. Since 512 and 125 have the same digits, they go in the same bucket. -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
