Well I thought it was fairly expensive, but I guess everything is relative.
It took 1.4 seconds using u\. and 1.3 using u/ .

On 5 Nov 2011, at 02:37, Henry Rich wrote:

> Yeah, unless your verb is expensive it's not worthwhile to avoid the 
> duplication.
> 
> Henry Rich
> 
> On 11/4/2011 10:10 PM, David Vaughan wrote:
>> Hm, seems that was actually slightly slower than using / .
>> 
>> On 5 Nov 2011, at 01:59, Kip Murray wrote:
>> 
>>> Here is an example (u is +)
>>> 
>>>    ]a =:>: i. 5
>>> 1 2 3 4 5
>>>    a +&.>  <\. a
>>> +---------+-------+-----+---+--+
>>> |2 3 4 5 6|4 5 6 7|6 7 8|8 9|10|
>>> +---------+-------+-----+---+--+
>>>    a +/ a
>>> 2 3 4 5  6
>>> 3 4 5 6  7
>>> 4 5 6 7  8
>>> 5 6 7 8  9
>>> 6 7 8 9 10
>>> 
>>> 
>>> On 11/4/2011 8:27 PM, David Vaughan wrote:
>>>> I have a dyadic verb which is applied on the same boxed list using x u/ y 
>>>> (where x=y), but this is inefficient because I only want to consider 
>>>> distinct pairs once. How can I do this?
>>>> 
>>>> Thanks.
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