It is "obvious" that if f is a dyadic function, then x f y is equivalent to f&>/(<x),(<y) . In some special (but not unusual) cases depending on x and y you can simplify this to f&>/x;y or f/x,:y .
On Fri, Nov 18, 2011 at 9:03 AM, Marc Simpson <[email protected]> wrote: > On Fri, Nov 18, 2011 at 4:39 PM, Roger Hui <[email protected]> > wrote: > > I have added a section of elementary examples. > > The observation about f/ on 2-item arrays is orthogonal and is "obvious". > > Thanks Roger, the elementary examples makes things much clearer. > > Regarding obviousness: I wasn't sure whether f//./ was considered a > pattern worth mentioning in its own right (I guess not). > > Best, > M > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
