The pattern is more apparent with 0.5*i.4 or -:i.4 than with 0 0.5 1 1.5,
and leads more readily to 0.5*i.2 4, -:i.10 4, etc.



On Tue, Dec 6, 2011 at 1:35 PM, Linda Alvord <lindaalv...@verizon.net>wrote:

> Start with 4 points on the x-axis of a real plane each 0.5 units apart
> going
> to the right and multiply by  0j1 :
>
>  j. d=:0 0.5 1 1.5
> 0 0j0.5 0j1 0j1.5
>
> The result is a set of points on a circle with r of  0.5 and center at (0.5
> 0) in an imaginary plane drawn from  (0 0) going clockwise.
>
> Multiply by  o.  and you get:
>
>    o.j. d=:0 0.5 1 1.5
> 0 0j1.5708 0j3.14159 0j4.71239
>
> a  set of 4 points in a line going up the  y  axis of an imaginary plane
> spaced o.%2  or  1.5708 units apart.
>
>
> Try:
>
>   (o.^:1 2 3 4)(j.^:1 2 3 4) d=:0 0.5 1 1.5
>
> But I digress.  I'm going back to ponder  [:   @    @:   in your message.
>
> Linda.
>
> -----Original Message-----
> From: programming-boun...@jsoftware.com
> [mailto:programming-boun...@jsoftware.com] On Behalf Of Kip Murray
> Sent: Tuesday, December 06, 2011 1:09 PM
> To: Programming forum
> Subject: Re: [Jprogramming] Turkey Roll - Challenge 2
>
>    NB. Roger is justly proud of
>
>    ^@o.@j. 1  NB. e ^ pi * i is _1
> _1
>
>    0 = 1 + ^@o.@j. 1  NB. Euler's 0 = 1 + e ^ pi * i five constants
> 1
>
>    ^ o. j. 1  NB. Approximates _1
> _1j1.22465e_16
>
>    NB. special code for ^@o.@j.
>
> On 12/6/2011 3:08 AM, Roger Hui wrote:
> >     ^@o.@j. 0 0.5 1 1.5
> > 1 0j1 _1 0j_1
> >
> >     ^@o.@j. 0.5 * i.5 4
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> >
> >     ^@o.@j. 1e9 + 0.5 * i.5 4
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> > 1 0j1 _1 0j_1
> >
> > 2011/12/6 Linda Alvord<lindaalv...@verizon.net>
> >
> >> Can you make a simple example that looks like this  u@v@w  ?  Please
> use
> ...
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