On Tue, Dec 6, 2011 at 11:32 AM, Linda Alvord <[email protected]> wrote:
> For number 2 each time you toss the dice, you must get a total for all the
> 500 dice. Next you toss the full bucket of dice 199 more times. Make a
> frequency distribution of the 200 results.
If I implement this description of number 2 I get almost 200 different
sums of the 200 throws of 500 dice, i.e. almost all of the sums have a
frequency of 1 (the odd one has 2 or 3).
platonic=: 4 6 8 12 20
sumtoss=: [: +/ ?@$
fd=: [: /:~ ({. , #)/.~
fd 500 200 sumtoss platonic
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