applying the definition of @ to the expression without the / might make it
clearer for a beginner to see what is happening.
   i=:(4 : '*:x+y')/
or
   i=:(13 : '*:x+y')/

Rephrased from the dictionary:

Apply the dyad, "Square the sum of the left and right arguments", between
the items.

On Sun, Feb 5, 2012 at 8:57 AM, Dan Bron <j...@bron.us> wrote:

> Linda, Boyko's not the first to express this sentiment to you.  Don't you
> wonder what the mysterious appeal of @ is?  If so, maybe a more rewarding
> (and commensurately challenging) exercise for you this morning is:
>
>        translate from expressions without @ to ones with it
>
> For example, you asked for a @-free translation of *:@+/ , and RE provided
> one.  What he didn't tell you is that *:@+/ is probably not what you're
> looking for in the first place.  Translating "square of the sum" into
> @-free J, we have ([: *: +/).  Now, can you (Linda, personally) find an
> equivalent verb, formulated using @ ?
>
> Good luck,
>
> -Dan
>
> PS:  Even harder challenge.  So hard that I'll open it up to everyone.
>  Express the original  *:@+/  in English.
>
>
>
>
> -----Original Message-----
> From: programming-boun...@jsoftware.com [mailto:
> programming-boun...@jsoftware.com] On Behalf Of Boyko Bantchev
> Sent: Sunday, February 05, 2012 9:17 AM
> To: Programming forum
> Subject: Re: [Jprogramming] Another early morning exercise
>
> On 5 February 2012 14:11, Linda Alvord <lindaalv...@verizon.net> wrote:
> > My goal has been to translate from expressions with �@ �to ones without
> it.
>
> You also mentioned eliminating @ in another thread.
> Why do you consider it important?
> @ is the composition of functions � and is composition not the most
> natural operation on functions that one could think of?
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