An interesting story. When I was teaching in about 1967 Friden came out with
a "box", larger than a typewriter, which could do square root
electronically! It cost $2000. I talked my Board of Education into
purchasing one for $1000 with an additional grant of $1000 which I got from
the NSF.  

I got one for maybe $3 as a stocking stuffer for my cousin at Christmas. It
was a flexible piece of plastic which would sort of stick to your pad or
desk.

You can't help but wonder what Pascal would have done with J ?

Linda

-----Original Message-----
From: programming-boun...@jsoftware.com
[mailto:programming-boun...@jsoftware.com] On Behalf Of Jose Mario Quintana
Sent: Monday, February 13, 2012 3:50 PM
To: Programming forum
Subject: Re: [Jprogramming] Challenge 5 Super Bowl Supposition

>That is the theoretical probability that A wins the series, given that A
>has won the first game.



I guess I can mention now, without the risk of spoiling anything, that the
essence of this problem can be traced al the way back to the origins of the
theory of probability (see http://www.businessweek.com/chapter/chap4.htm and
http://people.brandeis.edu/~cecchett/Textbook%20inserts/The%20Story%20of%20B
laise%20Pascal.htm).

________________________________________
From: programming-boun...@jsoftware.com [programming-boun...@jsoftware.com]
on behalf of Kip Murray [k...@math.uh.edu]
Sent: Monday, February 13, 2012 2:02 PM
To: Programming forum
Subject: Re: [Jprogramming] Challenge 5 Super Bowl Supposition

Here is a partial solution to Linda's Challenge 5.  --Kip Murray

Let us call the teams A and B.  A has won the first game of a seven game
series, and there are up to six games to go.  I deal with the question
of whether A wins the series, ignoring the matter of how many games are
required.  Each game is played until there is a winner -- there are no ties.

Let us imagine the teams play all six remaining games even if the series
is decided before the sixth remaining game.  Because the teams are
equally matched, the six remaining games are equivalent to six tosses of
a fair coin with sides 0 and 1, where 1 means a win by team A.  A key
idea is that A wins the series if A wins three or more of the remaining
six games, because then A has won four or more games in all and B has
won at most three games in all.

The binomial distribution (x!y)%(2^y) gives the probability of obtaining
exactly x heads in y tosses of a fair coin.  For six tosses the
probabilities are shown in the table

    (] ,: (2^6) %~ 6 !~ ]) i.7
        0       1        2      3        4       5        6
0.015625 0.09375 0.234375 0.3125 0.234375 0.09375 0.015625

We find the probability of three or more heads by summing:

    ([: +/ 3 }. (2^6) %~ 6 !~ ]) i.7
0.65625

That is the theoretical probability that A wins the series, given that A
has won the first game.

Verb winpct below simulates y repetitions of tossing a fair coin 6 times
and returns the percent of those y repetitions which resulted in 3 or
more heads.  (Heads is 1, tails is 0.)

    winpct =: 100 * ] %~ [: +/ 3 <: [: +/ [: ? 2 $~ 6 , ]

    winpct 2000000
65.6252

    winpct"0 [ 5#2000000
65.5622 65.6496 65.599 65.6166 65.6298


On 1/31/2012 3:46 AM, Linda Alvord wrote:
> Challenge 5 Super Bowl Supposition  PLEASE DO NOT RESPOND UNTIL 2/6/2012
12
> am EST
>
>
>
> As the Super Bowl approaches, suppose it will be decided like baseball.
Four
> of seven games determines a winner.  Also suppose that the NFL has won the
> first game.
>
>
>
> Simulate results of 2000000 series and provide the number of times the NFL
> wins in   4 5 6 7    games.  If the AFL wins this Extended Super Bowl
> Contest, the result is an  8 .  Create a  2000000 item list of number of
> games necessary to determine a winner and provide a frequency
distribution.
>
>
>
>           fd=: [: /:~ ({. , #)/.~
>
>     fd (expression for 2000000 trials)
>
> 4 249561
> 5 374865
> 6 373851
> 7 312603
> 8 689120
>
>     ]games=:fd n,.2000000$6
>
> 4 249301
> 5 376266
> 6 375281
> 7 311189
> 8 687963
>
>     ]prob=:(4+i.5),. (1{"1 games)%2000000
>
> 4 0.124651
> 5 0.188133
> 6  0.18764
> 7 0.155595
> 8 0.343982
>
>
>
>     ]+/(1{"1 games)%2000000
>
> 1
>
>
>
> Now, confirm  that your results are reasonable with a theoretical
argument.
>
>
>
> Also, enjoy the Super Bowl!
>
>
>
> Linda
>
>
>
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
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