Adam Judson napisał(a):
I thought I understood this...
I have
function A() = ...
A.prototype = {...}
and now I want to add
A.prototype.prototype = new SuperClass();
A.prototype.__proto__= new SuperClass()
or my favourite method
function A(){SuperClass.call(this, arg1, arg2); ...}
A.prototype = {
__proto__: SuperClass.prototype,
...
}
--
Pozdrawiam,
Pawel Chmielowski
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