Awesome, thanks!
On Fri, 17 Apr 2020 at 1:51 PM, Julius Volz <[email protected]> wrote:
> To get the total number of unique label pairs, you could get all label
> names via /api/v1/labels, and then for each label name, you'd have to run
> the query:
>
> count(count by(<labelname>) ({<labelname>=~".+"}))
>
> ...and then sum up all those results together.
>
> I don't think we have a handy way of getting the average bytes per label
> pair, but you could again get all label names like above, and then manually
> process the label pairs that appear in a query like this:
>
> count by(<labelname>) ({<labelname>=~".+"})
>
> You could write a small script / program that could do this via the API I
> guess.
>
> On Fri, Apr 17, 2020 at 10:41 AM Sohaib Omar <[email protected]> wrote:
>
>> Hi all, I was going through this blog :
>> https://www.robustperception.io/how-much-ram-does-prometheus-2-x-need-for-cardinality-and-ingestion
>> to
>> calculate Ram capacity for our Prometheus setup. I am bit confused about
>> how to find *unique label pairs across all time-series *and *Avg byte
>> per label pair. *Can someone help to find the formula for unique labels
>> across all time-series and avg byte per label?
>> Thanks
>>
>> --
>> You received this message because you are subscribed to the Google Groups
>> "Prometheus Users" group.
>> To unsubscribe from this group and stop receiving emails from it, send an
>> email to [email protected].
>> To view this discussion on the web visit
>> https://groups.google.com/d/msgid/prometheus-users/b0141b1e-6dc0-45f8-be20-d3aa17e28753%40googlegroups.com
>> <https://groups.google.com/d/msgid/prometheus-users/b0141b1e-6dc0-45f8-be20-d3aa17e28753%40googlegroups.com?utm_medium=email&utm_source=footer>
>> .
>>
>
--
You received this message because you are subscribed to the Google Groups
"Prometheus Users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/prometheus-users/CAHo%3DpzDYnSxnW2-P1ebf2MATU6TRktGMFSgn%2BOet_5JjX%3DRYXA%40mail.gmail.com.
