Thanks, I had no idea about the data method.
Much to learn.
Regards
Saptarshi
On Aug 24, 2009, at 4:09 PM, Kenton Varda <ken...@google.com> wrote:
> Yshould never use .c_str() in this case -- use .data() and .size()
> instead.
>
> On Mon, Aug 24, 2009 at 12:58 PM, Saptarshi Guha <saptarshi.g...@gmail.com
> > wrote:
> Hello,
> Thank you! Being new to c++ i had no idea of the size method. I was
> thinking of strlen on c_str() which would have given me the wrong
> number of bytes.
> Nice and clean now.
> Regards
> Saptarshi
>
>
> On Mon, Aug 24, 2009 at 3:21 PM, Kenton Varda<ken...@google.com>
> wrote:
> > In C++, "bytes" fields are stored using std::string. This class
> has a
> > size() method which returns the length of the string. So, the
> length of
> > sdata1 is:
> > message.sdata1().size()
> > So you want to use option (A).
> > You would use option B if you wanted to store multiple independent
> byte
> > strings, each one containing an arbitrary number of bytes. There
> is never a
> > reason to use option C.
> > On Mon, Aug 24, 2009 at 7:51 AM, Saptarshi
> <saptarshi.g...@gmail.com> wrote:
> >>
> >> Hello,
> >> Suppose I would like to store a type that could be a sequence of
> raw
> >> bytes, so
> >>
> >> message ...{
> >>
> >> optional bytes sdata1=1; //A
> >> repeated bytes sdata2=2; //B
> >> optional BYT sdata3=3; //C
> >> }
> >>
> >> message BYT{
> >> uint32 length=1;
> >> bytes data=2;
> >> }
> >> Now I have a unsigned char * array which I wish to store in the
> >> message.
> >>
> >> My first approach was using (B), add_sdata2(array[i],i) (something
> >> similar), but this is 3bytes per byte stored.
> >>
> >> I then tried, option A, storing the entire set of data into sdata1
> >> (which is actually a string, according to the generated protobuf
> >> header files). But when it comes to reading it, how do i know the
> >> number if bytes stored in the string? Suppose I my data looks like
> >> 0x00,0x00,0x00, what will be the length?
> >>
> >> I am currently using option (c).
> >>
> >> Have I missed something? Is there a better approach.
> >> Thank you in advance
> >> Saptarshi
> >>
> >> > >>
> >
> >
>
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