So, the cpprefernce page on template type deduction seemingly suggests you
can: http://en.cppreference.com/w/cpp/language/template_argument_deduction
On Thu, May 19, 2016, 6:09 PM Feng Xiao <xiaof...@google.com> wrote:
>
>
> On Thu, May 19, 2016 at 10:31 AM, Alex Shaver <alexsha...@gmail.com>
> wrote:
>
>> Suppose I have a message:
>> message Foo{
>> oneof b_message {
>> Bar = 16;
>> Baz = 17;
>> }
>> }
>>
>> and I have some C++ handler that is a templated function:
>> template<class T>
>> void b_handler(const T&);
>> template void b_handler(const Bar& bar){...}
>> template void b_handler(const Baz& baz){...}
>>
>> What I'd like to be able to do is:
>> void foo_handler(const Foo& foo){
>> ...
>> b_handler(foo.b_message());
>> }
>>
>> Essentially, if protoc generated some kind of function like
>> template<class T>
>> const T& Foo::b_message() const;
>> const Bar& Foo::b_message() const;
>> const Baz& Foo::b_message() const;
>>
>> that would make for automatic handling of whatever kind of b_message Foo
>> had carried, rather than doing a switch(foo.b_message_case()) type decision
>> tree.
>>
> It's pretty easy to write a protoc plugin to generate additional code.
> What I don't understand though is how can you have two methods with the
> same signature return different types? Is that supported by C++?
>
>
>>
>> I'm sure there are a lot of edge cases that I'm not thinking of, or
>> cross-language considerations, but is anything like this possible?
>>
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