$("main_content").fade({ duration : 1.6, afterFinish : function(fx){
fx.element.update("<img src='spin2.gif'/>");
fx.element.appear({ duration : 1.0 });
}
On Nov 12, 10:32 am, Walter Lee Davis <[EMAIL PROTECTED]> wrote:
> Use a queue, or create a new hidden image over top of the old and
> fade that one up. (The latter looks exactly like a cross-fade, if
> that's the effect you're after.)
>
> Walter
>
> On Nov 12, 2008, at 9:19 AM, [EMAIL PROTECTED] wrote:
>
>
>
> > Hi, currently i have this statement:
>
> > $('main_content').fade({duration: 1.5}).update('<img src="spin2.gif"/
> >> ').appear({ duration: 1.0 });
>
> > but the content will update and than fade... how do i make it fade the
> > old content, update the content and show it?.
>
> > thanks
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