This is untested, but I would probably do something like this:
$$('form[name=login_form]').invoke('observe', 'keydown', function(event)
{
if (event.keyCode === 13) {
event.findElement('form').submit();
}
});
-Hector
On Wed, Dec 10, 2008 at 4:46 AM, Dave L <[EMAIL PROTECTED]> wrote:
>
> Im not sure I understand. login_form is the id of the form that I am
> trying to submit. and form_submit is the id of the actual submit
> button. I tried the following:
>
> document.form.login_form.onkeydown="if(event.keyCode==13)
> {this.form.submit();return false;};"
>
> and also
>
> $('login_form').form_submit.onkeydown="if(event.keyCode==13)
> {this.form.submit();return false;};"
>
> but no go. Thanks for your input.
>
> On Dec 10, 1:03 am, "pradeep saraswati" <[EMAIL PROTECTED]> wrote:
> > > hai
> >
> > u are using $('form_submit') --------does form_submit is the id of the
> > form....
> >
> > then it will surely does not gonna work in I.E
> >
> > so you specify a name to the form....and access the form....
> >
> > document.form.formname.onkeydown--------> this will work in ie...
> >
> > i too faced this issue....just try this u r problem will be solved....
> >
> > if u are too much particular in accessing form using $...then use $F and
> > never access form using the id
> > IE will never know..what you are doing...if you access form by id
> >
> > Regards
> > spradeepkumar
> >
>
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