On Dec 17, 2:12 am, kangax <kan...@gmail.com> wrote:
> Michael wrote:
> > This is awesome - I am totally almost getting this!
>
> > What if my Coupon Code started at some number mid sequence - like
> > everything
> > greater then
>
> > C32456 would be valid...
>
> It's almost always a pain to work with numeric ranges in regex. I
> think the best option in this case is to parse sequence as a number
> and just use comparison operators. Something like:
>
> var passed = false;
> var match = 'C32456'.match(/\d+/);
> if (match && match[0]) {
> match = parseInt(match);}
Will that result differ from:
var match = parseInt('C32456');
>
> if (!isNaN(match)) {
> passed = (match > 1234);
There is no need to use parseInt. During evaluation of the '<'
operator, if one expression is a Number, the other will be converted
too. A simpler algorithm finds the number part by simply removing
leading non-digits, so:
var s = 'C32456';
passed = s.replace(/^\D+/,'') > 1234;
A RegExp test should probably be done first to ensure the correct
format before testing that the number part is in range, so something
like the following may do:
if (/^C\d+$/.test(s) && s.replace(/^\D+/,'') > 1234) {
// coupon OK
}
adjusted for whatever formats need testing. If there are many
formats, a function could be written to test the format (passed as a
RegExp) and that the number part is within a certain range, something
like:
function testCoupon( s, formatRE, min, max) {
var n = s.replace(/^\D+/,'');
return re.test(s) && n >= min && n <= max;
}
and
testCoupon('C123', /^C\d+$/, 0, 1000)
--
Rob
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