TJ, thanks for correcting the docs. I hadn't noticed that error
either.
Are you suggesting that there no intersection of Prototype and Ruby
communities? I only know of Prototype because of Ruby on Rails.
Let's take Hash#reject() as an example. Let's say I'm moving server-
side Ruby code to my Prototype-enhanced client-side.
Ruby code:
{ "a" => 100, "b" => 200, "c" => 300 }.reject {|key, value| key ==
"b" }
=> {"a"=>100, "c"=>300}
Translated to Javascript:
$H({ "a": 100, "b": 200, "c": 300 }).reject(function(i) { return i.key
== "b" })
=> [["a", 100], ["c", 300]]
Prototype returns an array? What good is an array if I started with a
hash? It is intuitive that a reject() method returns a subset of the
original data structure and not convert it to an entirely different
one.
Perhaps this is a plea better left for the Prototype-core list.
On Feb 3, 6:18 am, "T.J. Crowder" <t...@crowdersoftware.com> wrote:
> Hi,
>
> > Maybe filter should be an alias of findall for arrays, but shouldn't
> > it really return a hash for hashes?
>
> FWIW (and it ain't much, I'm not a decision maker on Prototype stuff),
> in my opinion it would be an _extremely_ bad idea for Hash to break
> the contract documented for Enumerable.
>
> > ...in ruby, which Prototype is supposed to be modeled after.
>
> Prototype has been split off from Ruby for a long time now. I'd
> venture to say that most people using Prototype do not use and may
> well never have even seen Ruby. PHP seems to be the server-side
> language I see most in code snippets from people asking questions.
> --
> T.J. Crowder
> tj / crowder software / com
> Independent Software Engineer, consulting services available
>
> On Feb 3, 2:04 pm, disccomp <discc...@gmail.com> wrote:
>
> > Maybe filter should be an alias of findall for arrays, but shouldn't
> > it really return a hash for hashes? Especially if thats its behavior
> > in ruby, which Prototype is supposed to be modeled after.
>
> > On Feb 3, 4:59 am, "T.J. Crowder" <t...@crowdersoftware.com> wrote:
>
> > > Hi Brad,
>
> > > Sorry, I missed that Hash inherits from Enumerable (and I've filed a
> > > doc bug on it[1] and will fix it -- the doc page for Hash doesn't
> > > mention Enumerable).
>
> > > So I think that's your answer: Hash#filter is an alias for
> > > Enumerable#findAll[2], which is documented as returning an array, not
> > > a Hash, and so having it return a Hash would be breaking the contract.
>
> > > [1]http://prototype.lighthouseapp.com/projects/8886-prototype/tickets/535
> > > [2]http://prototypejs.org/api/enumerable/findall
>
> > > Sorry again to have missed the Enumerable thing in the first place.
> > > --
> > > T.J. Crowder
> > > tj / crowder software / com
> > > Independent Software Engineer, consulting services available
>
> > > On Feb 3, 12:25 am, Brad <bradavo...@gmail.com> wrote:
>
> > > > It does. Hash still inherits from Enumerable, hence the usage of
> > > > Hash#findAll().
>
> > > > - Brad
>
> > > > On Feb 2, 1:34 am, ColinFine <colin.f...@pace.com> wrote:
>
> > > > > On Jan 31, 11:11 pm, Brad <bradavo...@gmail.com> wrote:
>
> > > > > > Yup, found it -http://dev.rubyonrails.org/ticket/3592
>
> > > > > > It is indeed a bug in Prototype that hasn't been addressed.
>
> > > > > > - Brad
>
> > > > > But it seems to me that it's gone away, because Hash no longer mixes
> > > > > in Enumerable, does it?
>
> > > > > Colin
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