On Apr 13, 6:25 pm, mr_justin <gro...@jperkins.otherinbox.com> wrote:
> > This is a regression.
> OK, that's good to hear.
> > so `$A('one', 'two', 'three')`, as in your example, should
> > produce - ['o', 'n', 'e'].
> That doesn't seem right. In the past, it has always produced a 3-item
> array out of the arguments, not the characters of the first argument.
> Essentially behaving just like a normal square bracket-declared array.
> I used this technique quite a bit because it was easy to go from
> ['one', 'two', 'three'] to $A('one', 'two', 'three').

At least has already been operating on `iterable` which is a
first argument of `$A`. Do you remember which version was flattening
all of the arguments?

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