Hi,
I can think of two approaches off-hand:
1. Use Enumerable#include on the array of classes you want to test
against, using Element#hasClassName as the iterator function (bound to
the instance), e.g.:
var test = ['foo', 'bar', 'foob'];
if (test.any(element.hasClassName.bind(element))) {
// ...
}
or
if (['foo', 'bar', 'foob'].any(element.hasClassName.bind
(element))) {
// ...
}
(You don't need to use $A() around array literals.)
2. Use $w on the class name to get an array of the individual class
names, then use Enumerable#any on that, passing in Enumerable#include
on the array you want to test against as the #any iterator. Something
like this:
var test = ['foo', 'bar', 'foob'];
if ($w(element.className).any(test.include.bind(test))) {
log("true");
}
(Both of those bits of code are untested.)
But if this is going to be happening a lot (a tight loop, or a
mouseover handler, etc.), check the runtime cost of each of these by
going under the covers.
FWIW,
--
T.J. Crowder
tj / crowder software / com
Independent Software Engineer, consulting services available
On May 13, 7:34 pm, louis w <[email protected]> wrote:
> I have an array containing a number of strings. I would like to
> continue exucuting my script only if an item has ANY/ALL of the
> strings assigned as a class name.
>
> $A(['foo', 'bar', 'foob']);
>
> Is there an elegant want to do this without having to loop through the
> items?
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