> Isn't closure formed in both #1 and #2 as soon as FunExpr. (passed to > `each`) is being evaluated?
Right, I was assuming correct syntax for #1 (my bad): $R(1,2).each(this.bar, this); which avoids the extra closure altogether. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Prototype & script.aculo.us" group. To post to this group, send email to prototype-scriptaculous@googlegroups.com To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en -~----------~----~----~----~------~----~------~--~---
