mr_justin wrote: >> but the fact is, I have several arguments, not >> just one. I want to treat the first argument as an Enumerable, and the > > I see, that wasn't clear from the beginning. > > In that case, how about: > > elements = $A([elements]).flatten(); > handlers = $A([handlers]).flatten(); Here's how I use to do it: var sth_as_array = $A(Object.isArray (sth) ? sth : [sth]);
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