> When i call this function the return always false. Obviously because
> onsuccess create another function and it doesn't change the value of
> external variable.
>
> I'm asking for you guys if there's some way to change the value of
> variable logged based on the return of the ajax call? Or there's a way
> inside onSuccess to return the response to the caller function?
>

No, neither.

Your function userLogged has (in general) finished and returned before
the Ajax call returns - probably before it is even sent.

You need to restructure your code to take account of the asynchronous
nature of Ajax (don't be tempted to run it synchronously: this is a
bad idea).

Sorry.
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