Hi, again
Sorry for being obtuse.  But can someone help me and even understand how to
write a function and call it on a hash that will take a value, compare it
against each of the keys in the hash, on match delete the key/value, and
return the hash.  tia.

On Thu, Apr 8, 2010 at 5:24 PM, chrysanthe m <chrysant...@gmail.com> wrote:

> Hi Alex
> Thanks, but a newbie here so that was "drinking at a firehose".  Let me
> parse it to better understand.
> First can you really invoke on two separate enumerable objects with that
> [n,n1,n2] syntax?  That is tremendous.
> My problem is I need to first check the presence of a key before I unset it
> b/c I found out unset-ing a non-existent key seems to zero the struct; also
> it is more courteous, grin.  So how would I construct the and parameterize
> the annonymous function to do the check and if present "do it to itself".
> Ideally I would like to pass in the enumerable, call the function and return
> the modified(or not) enumerable in the function's return.
>
> On Thu, Apr 8, 2010 at 4:41 PM, Alex Wallace <alexmlwall...@gmail.com>wrote:
>
>> Ah, I see. You can handle this using Enumerable's invoke. This code should
>> make it clear:
>>
>> a = new Hash({ x : "foo", y : "bar" });
>> b = new Hash({ x : "zam", y : "moof" });
>> a.get("x");
>>   "foo"
>> b.get("x");
>>   "zam"
>> [a,b].invoke("get","x");
>>   ["foo", "zam"]
>> [a,b].invoke("unset","x")
>>   ["foo", "zam"]
>> a.get("x")
>>   (undefined)
>>
>> Cheers,
>> Alex
>>
>>  On Thu, Apr 8, 2010 at 3:24 PM, chrysanthe m <chrysant...@gmail.com>wrote:
>>
>>>  Sorry sudden send resume in this reply
>>>
>>> Hello
>>> I am having a difficult time trying to enumerate a hash to determine if a
>>> give key is in the hash and if so delete it and its value.
>>> If I could approach it index it would be
>>> function remove(valueToTest, hashToBeTested){
>>>    for(i=0;i<hashToBeTested.length;i++){
>>>       if(valueToTest==hashToBeTested[i])
>>> hashToBeTested.unset(valueToTest);
>>>    }
>>>
>>> Would I do it like
>>>
>>> hashToBeTested.each(function(valueToTest){
>>>   if(valueToTest==this)hashToBeTested.unset(valueToTest);
>>>   },hashToBeTested);
>>> return hashToBeTested;
>>>
>>>
>>> which I am sure is wrong syntactically if not semantically.  Can someone
>>> guide the proper way and more deeply the use of this?
>>>
>>>
>>> On Thu, Apr 8, 2010 at 3:06 PM, chrysanthe m <chrysant...@gmail.com>wrote:
>>>
>>>>
>>>>
>>>
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>

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