Thanks Richard for your answer on this! Question regarding this:
> Object.extend(..., options || {}) // Extend the object created about
Is it necessary to || {} (empty object) so as to not break the
Object.extend in the event that options is null?
Karl..
On Aug 31, 10:19 am, Richard Quadling <rquadl...@gmail.com> wrote:
> On 31 August 2010 17:49, kstubs <kst...@gmail.com> wrote:
>
>
>
>
>
> > Hello,
> > Full credit to: Matthew Foster for the code below. I'd like an
> > explanation of the below. I'm having some troubles with Object extend
> > and would like a better explanation of the magic that occurs below.
>
> > $C = function(name, options) {
> > return Element.extend(Object.extend(document.createElement(name ||
> > "div"), options || {}));
> > }
>
> > Sample use:
> > var next = $C("td", { innerHTML: ">", className: "next" });
>
> > So how are the properties innerHTML and className morphed on to this
> > new td element?
>
> > Thanks,
> > Karl..
>
> Object.extend takes a set of name/value pairs and applies them to
> whatever object it is extending.
>
> So, innerHTML and className, both properties of the DOM element TD,
> get assigned by Object.extend.
>
> Taking the code inside out ...
>
> document.createElement(name || "div") // Create an element based of
> the type defined by the value of name or a div, if no name is
> supplied.
> Object.extend(..., options || {}) // Extend the object created about
> with the name/value pairs in options, or not, if no options have been
> supplied.
> Element.extend(...) // Same as $(...);
>
> Hope that helps.
>
> --
> Richard Quadling
> Twitter : EE : Zend
> @RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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