Hi,
The `for..in` loop enumerates the *names* of the properties in the
object and its prototype(s); your `m` is always a string because
property names are always strings. To get the property value, just
look it up as normal:
for (name in c) {
console.log(name + " [" + typeof c[name] + "]");
}
(Or instead of `typeof` you have other options[1], but you get the
idea.)
As a bonus answer, if you want to differentiate between properties on
the object itself and properties that it's inheriting from its
prototype chain, use `hasOwnProperty`:
for (name in c) {
console.log(
name + " [" + typeof c[name] + "] (" +
(c.hasOwnProperty(name) ? "own" : "inherited") +
")"
);
}
Live example: http://jsbin.com/ekimu4
[1] http://blog.niftysnippets.org/2010/09/say-what.html
HTH,
--
T.J. Crowder
Independent Software Engineer
tj / crowder software / com
www / crowder software / com
On Mar 17, 4:53 pm, greg <g...@reservation-net.com> wrote:
> Hi,
>
> Within my script I'd like to get a list of methods defined within in a
> class created with Class.create().
>
> If I do:
> var c = new MyShinyNewClass()
> console.log(c)
> I get a nice breakdown of variables and methods, and firebug
> differentiates the vars from the functions.
>
> If I do:
> for (m in c) console.log(m)
> I get a nice list of all variables and methods, but typeof m always
> returns 'string'.
>
> Given that firebug can differentiate between a variable and function,
> is there any way for me to do the same?
>
> Thanks.
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