I'm sorry, what I meant was this.superclass In Prototype's class 
implementation you can see that if you provide a parent-class in prototype's 
Class.Create-Method, that class will be referenced as superclass in the 
class you are creating:

  function create() {
    var parent = null, properties = $A(arguments);
    if (Object.isFunction(properties[0]))
      parent = properties.shift();

    // ...

    klass.superclass = parent;

    // ...

    return klass;

why not just use this.superclass.method in the subclass?

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