Hi,
[EMAIL PROTECTED] wrote on 31.03.2008 17:05:35:
> So the arguments are expanded as you described, the $(and) function
expands to
> the expansion of the last argument (y), which is != nothing.
>
> Should be right. Stand alone example:
>
> [EMAIL PROTECTED]:~$ cat Makefile
> BAZ=$(and $(FOO),$(BAR))
>
> all:
> @echo $(BAZ)
> [EMAIL PROTECTED]:~$ make FOO= BAR=
>
> [EMAIL PROTECTED]:~$ make FOO=y BAR=
>
> [EMAIL PROTECTED]:~$ make FOO= BAR=y
>
> [EMAIL PROTECTED]:~$ make FOO=y BAR=y
> y
>
> Q.E.D.
If i do the same, the result is different... but why ?
[EMAIL PROTECTED]:~> cat Makefile
BAZ=$(and $(FOO),$(BAR))
all:
@echo $(BAZ)
[EMAIL PROTECTED]:~> make FOO= BAR=
[EMAIL PROTECTED]:~> make FOO=y BAR=
[EMAIL PROTECTED]:~> make FOO= BAR=y
[EMAIL PROTECTED]:~> make FOO=y BAR=y
[EMAIL PROTECTED]:~>
Maybe the 'make' version ?
[EMAIL PROTECTED]:~> make -v
GNU Make 3.80
Copyright (C) 2002 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.
There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A
PARTICULAR PURPOSE.
[EMAIL PROTECTED]:~>
-Jürgen
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