Ian Hickson: > I don't really mind exactly what the solution is; my only concern here > would be that I'd be throwing [PrototypeRoot] around a lot.
Acknowledged. If you can propose a way of defining this without needing to use [PrototypeRoot] a lot, that’d help. > (I assume with PrototypeRoot that the most-derived interface that > inherits from such an interface is automatically promoted to being the > [[Class]]?) That’s right. -- Cameron McCormack ≝ http://mcc.id.au/
