Issue #13210 has been updated by eric sorenson.

FWIW in 3.x as it stands, the sample code behaves as Timur expected:

<pre>
[[email protected] ~/Sandbox/puppet-undef/manifests]% puppet apply 
--modulepath=/Users/eric/Sandbox 13210-undef-back-from-functions.pp             
                                                                                
             Error: Duplicate declaration: Notify[x] is already declared in 
file 
/Users/eric/Sandbox/puppet-undef/manifests/13210-undef-back-from-functions.pp 
 at line 2; cannot redeclare on node
</pre>
----------------------------------------
Bug #13210: undef changes into '' when passed to function as a param
https://projects.puppetlabs.com/issues/13210#change-69625

Author: Timur Batyrshin
Status: Duplicate
Priority: Normal
Assignee: 
Category: 
Target version: 3.x
Affected Puppet version: 
Keywords: 
Branch: 


Suppose we have a manifest like that:
<pre>
define foo ( $x = '1' ) {
  notify { "x${x}": }
}

class bar {
  $x = myfunc( undef )
  foo {'no1': x=> $x }
}

class baz {
  $x = undef
  foo {'no2': x=> $x }
}


include bar
include baz
</pre>

With myfunc() defined like that:
<pre>
module Puppet::Parser::Functions
    newfunction(:myfunc, :type => :rvalue) do |param|
      return param
    end
end
</pre>

When applying the manifest we get the following output.
<pre>
notice: x
notice: /Stage[main]/Bar/Foo[no1]/Notify[x]/message: defined 'message' as 'x'
notice: x1
notice: /Stage[main]/Baz/Foo[no2]/Notify[x1]/message: defined 'message' as 'x1'
notice: Finished catalog run in 0.06 seconds
</pre>

However the same message should be produced in both calls to foo.



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