Hi,
I have the following code snippet
node default {
# $var_a .. is undefined
$var_b = hiera("var_b", undef)
$var_c = undef
file { "/var/tmp/foo.txt": content => inline_template("
<% if @var_a %>
var_b = <%= @var_a %>
<% else %>
<% info(\"var_a is undefined\") %>
<% end -%>
<% if @var_b %>
var_b = <%= @var_b %>
<% else %>
<% info(\"var_b is undefined\") %>
<% end -%>
<% if @var_c %>
var_c = <%= @var_c %>
<% else %>
<% info(\"var_c is undefined\") %>
<% end -%>
"
), }
}
Applying it, will generate these two info messages.
Info: template[inline]: var_a is undefined
Info: template[inline]: var_c is undefined
var_b =
What I would like puppet to do is to fail if template is referencing a
variable which is not defined, without having to wrap it with
if-else-fail()-end.
Another strange thing I've noticed that "undef" behaves differently if it
is a default value for hiera lookup (see var_b vs var_c).
Actually, my code looks more like..
$var_a = hiera("var_a")
$var_b = hiera("var_b")
$var_c = hiera("var_c")
file {"..": content => template(hiera("tmpl_name")) }
That will fail if any variable a,b,c is undefined in hiera, no matter if it
is used in template or not. I can rewrite it to
$var_a = hiera("var_a", undef)
$var_b = hiera("var_b", undef)
$var_c = hiera("var_c", undef)
file {"..": content => template(hiera("tmpl_name")) }
This will not fail even if variable used by the template is undefined. The
value is quietly replaced by empty string.
In other words, I would like to delay the failure from hiera() lookup to
the time when it is actually used in template. Can it be done without
explicitly testing it with "if" inside template ?
Thanks,
BranoZ
PS: we are (or soon be) on puppet 3.2.
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