[email protected] wrote on Fri, 04 Sep 2009 09:29 -0400:
> Pete Wyckoff wrote:
> > [email protected] wrote on Thu, 03 Sep 2009 16:31 -0400:
> >> But Pete, the problem is encode_string does not write 8 bytes of 0, it  
> >> writes 4 bytes of 0.  If the buffer is 0's to start with what is here  
> >> works fine, but if there is something else in the field you get garbage.
> >>
> >> Seems like a prudent move to simply zero out all 8 bytes instead of just  
> >> 4, wouldn't you say?
> > 
> > Thanks for explaining.  I'm looking at the wrong end of the problem,
> > maybe.
> > 
> > On the encode side, we have
> > 
> >     #define encode_string(pptr,pbuf) do { \
> >     u_int32_t len = 0; \
> >     if (*pbuf) \
> >         len = strlen(*pbuf); \
> >     *(u_int32_t *) *(pptr) = htobmi32(len); \
> >     if (len) { \
> >         memcpy(*(pptr)+4, *pbuf, len+1); \
> >         *(pptr) += roundup8(4 + len + 1); \
> >     } else { \
> >         *(u_int32_t *) (*(pptr)+4) = 0; \
> >         *(pptr) += 8; \
> >     } \
> >     } while (0)
> 
> There's the mixup, we're looking at different versions of encode_string!
> From a fresh 2.8.1 and the branch I'm working from I have the following
> encode_string:
> 
> #define encode_string(pptr,pbuf) do { \
>     u_int32_t len = 0; \
>     if (*pbuf) \
>         len = strlen(*pbuf); \
>     *(u_int32_t *) *(pptr) = htobmi32(len); \
>     if (len) { \
>         memcpy(*(pptr)+4, *pbuf, len+1); \
>         int pad = roundup8(4 + len + 1) - (4 + len + 1); \
>         *(pptr) += roundup8(4 + len + 1); \
>         memset(*(pptr)-pad, 0, pad); \
>     } else { \
>         *(u_int32_t *) *(pptr) = 0; \
>         *(pptr) += 8; \
>     } \
> 
> In the else branch there is no +4 in the *pptr assignment. Which branch
> are you working from? It looks like this was already addressed somewhere
> before?

I go to pvfs.org/fisheye.  Looking at cvs vers 1.27 now.  I was
quoting the non-valgrind one.  Which seems to be different from the
valgrind one you quote above in this important way.  My vote goes
toward fixing the valgrind version to fix the off-by-4 bug you just
found.  It's old, apparently, but would only hurt if you configured
--with-valgrind.

Good catch.  Looking at that mess of #defines is always a challenge.

                -- Pete

> > 
> > For a NULL pbuf, or a non-NULL pbuf that starts with'\0',
> > we get:
> > 
> >     len = 0
> >     pptr[0..3] = 0
> >     (take the else clause)
> >     pptr[4..7] = 0
> >     (pptr offset up by 8)
> > 
> > That generates 8 bytes okay.
> > 
> > For any other pbuf with len > 0, say 1 for "a\0", we get:
> > 
> >     len = 1
> >     pptr[0..3] = htonl(1)
> >     (take the if clause)
> >     pptr[4..7] = 'a' '\0' 'x' 'x'   /* 'x' == garbage */
> >     (pptr offset up by 8)
> > 
> > Is it those two bytes of 'x' that you don't like?  That's why
> > we have the valgrind ifdef.  What am I missing?
> > 
> > Michael's initial patch was:
> > 
> >     131c131,134
> >     <     memcpy(pbuf, *(pptr) + 4, len + 1); \
> >     ---
> >     > >     if( len ) \
> >     > >         memcpy(pbuf, *(pptr) + 4, len + 1); \
> >     > >     else \
> >     > >         memcpy(pbuf, *(pptr), len + 1); \
> > 
> > Unfortunately without the useful "-u -p" args to diff, but eyeing
> > the source shows he's patching on the decode side.
> > 
> >             -- Pete
> > 
> 
> Apologies for the lack of context on the diff but you're right it was on
> the decode side. However, when you mentioned the encode side always
> shipped 8 bytes I looked closer at the encode side and saw in this
> version only 4 of the 8 bytes were getting set to '\0'.
> 
> Michael
> 
> >> Pete Wyckoff wrote:
> >>> [email protected] wrote on Thu, 03 Sep 2009 13:44 -0400:
> >>>> Pete Wyckoff wrote:
> >>>>> [email protected] wrote on Thu, 03 Sep 2009 11:51 -0400:
> >>>>>> In looking at some issues I was having with the encoding of PVFS_dirent
> >>>>>> structs in requests I saw an inconsistency in how here_strings are
> >>>>>> encoded and decoded. encode_string memcpys strings starting at 
> >>>>>> *(pptr)+4
> >>>>>> unless it's length 0 in which case it sets *(pptr) to 0. However,
> >>>>>> decode_here_string always copys from *(pptr) + 4. So, if d_name is an
> >>>>>> empty string when encoded d_name gets 1 byte of *(pptr)+4 instead of 0
> >>>>>> on decoding.
> >>>>>>
> >>>>>> The fix is just to handle decoding like encoding. Is there a reason for
> >>>>>> always copying to *(pptr)+4 in decode_here_string? Is this something
> >>>>>> that should be changed?
> >>>>> encode_string always ships at least 8 bytes.  For a null string, that's 
> >>>>> 8
> >>>>> bytes of zeroes.  Decoding a null "here" string will use one of
> >>>>> those zero bytes to set pbuf[0] = '\0'.  I figured it would be nice
> >>>>> to make sure the string was set to NULL.
> >>>>>
> >>>> I see where 8 bytes are always shipped in encode_string but I'm not
> >>>> seeing where 8 bytes of '\0' get encoded for a NULL string or if the
> >>>> length of the string is 0.
> >>>>
> >>>> However, adding an 8 byte memset worth of '\0' to *(pptr) in the else
> >>>> (length 0) branch of encode_string also resolves the problem I was
> >>>> seeing. So, your point may make for a better solution.
> >>>     uint8_t *wiredata;
> >>>     char mystr[20];
> >>>     decode_here_string(&wiredata, mystr);
> >>>
> >>>     wiredata -> 0 0 0 0 0 0 0 0
> >>>     mystr unititialized
> >>>
> >>> 131            memcpy(pbuf, *(pptr) + 4, len + 1); \
> >>>
> >>>     memcpy(pbuf, <bunch of zeroes>, 1)
> >>>     equiv to
> >>>
> >>>     pbuf[0] = '\0';
> >>> or
> >>>     mystr[0] = '\0';
> >>>
> >>> right?  It's a _here_ string, you don't want to destroy the pointer,
> >>> you want to put a zero into it to nullify the string.
> >>>
> >>> The comment does say "odd variation".  I don't remember where this
> >>> even gets used.
> >>>
> >>>           -- Pete
> >>> _______________________________________________
> >>> Pvfs2-developers mailing list
> >>> [email protected]
> >>> http://www.beowulf-underground.org/mailman/listinfo/pvfs2-developers
> 
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