Thomas Unterthiner <[email protected]> writes: > Hi! > > I have a program that makes extensive use of pycuda, but also calls out > to a C library which also uses CUDA internally (it does not share any > state or memory with the pycuda code, and uses the CUDA runtime API). > However, after the call to the C library ends, all my PyCUDA calls fail > with a "LogicError: cuFuncSetBlockShape failed: invalid handle". (The > same call with the same parameters worked fine before calling out to the > C library). > > I have tried explicitly initializing/shutting down the PyCUDA contexts, > but I still can't get stuff to work. The relevant parts of my program > look as follows: > > > # initialize PyCUDA > def init_pycuda(gpu_id): > import pycuda.driver as cuda > global __pycuda_context, __pycuda_device > pycuda_drv.init() > __pycuda_device = pycuda_drv.Device(gpu_id) > __pycuda_context = __pycuda_device.make_context() > import scikits.cuda.misc > scikits.cuda.misc.init() > > init_pycuda(0) > use_pycuda() > > # trying to shut down PyCUDA > import scikits.cuda.misc > from pycuda.tools import clear_context_caches > cuda_memory_pool.free_held() > cuda_hostmemory_pool.free_held() > scikits.cuda.misc.shutdown() > __pycuda_context.pop() > clear_context_caches() > __pycuda_context = None > __pycuda_device = None > > > # ... now I'm calling out to the other library > call_external_library() > > init_pycuda(0) > use_pycuda() # this will now fail with a LogicError > > > As said before, the C library uses the CUDA runtime API, so it uses > cudaSetDevice to initialize and calls cudaDeviceReset at the end. Is > there something I'm overlooking wrt. how to (de)initializing PyCUDA?
Does the C library document what it does in regards to context management? Also, to the best of my knowledge, the CUDA driver library offers no possibility to "shut down" CUDA once it's initialized, so PyCUDA can't do that either. HTH, Andreas
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