On Mon, Jul 23, 2012 at 1:49 PM, anatoly techtonik <[email protected]>wrote:
> On Mon, Jul 23, 2012 at 8:31 PM, Tristam MacDonald <[email protected]> > wrote: > > On Mon, Jul 23, 2012 at 6:46 AM, anatoly techtonik <[email protected]> > > wrote: > >> > >> Hi, > >> > >> What is the correct way to initiate window redraw? > > > > > > What's wrong with scheduling an update function? IIRC, that should > trigger a > > redraw whenever it occurs. > > > > def update(dt): > > pass > > > > pyglet.clock.schedule_interval(update, 1/60.0) > > Thanks. Surprisingly, an empty update() call kicks event loop as > expected. I want to measure maximum FPS possible on 100% CPU load, so > a 1/10000 value looks good for my case. But for the clarity I'd still > prefer to kick event loop explicitly. Unfortunately, Google Code > Hosting is down at the moment and don't allow me to browse the sources > to see how is it implemented. > -- > anatoly t. Ok, so it's not really possible to do so unless you implement your own event loop. The default event loop redraws every window for which window.invalid == True (which it is by default), every time through the event loop. If you want to redraw as fast as possible, you do exactly as you did (schedule a high frequency update function), because each time that is called the event loop is run, and redraw will happen. -- Tristam MacDonald http://swiftcoder.wordpress.com/ -- You received this message because you are subscribed to the Google Groups "pyglet-users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/pyglet-users?hl=en.
