maybe
def update(self, dt):
self.base.x = (self.base.x - 30 * dt) % self.base.shift
?
On Tue, Jun 16, 2015 at 4:07 PM, NiBE <adolfa.tedo...@gmail.com> wrote:
>
> HI,
> I'm trying to convert a simple game written in pygame in pyglet. I almost
> figure out everything, but now I'm facing this situation, I have a
> background sprite like this example:
>
>
> <https://lh3.googleusercontent.com/-2dm2ybJClP4/VYBzG7LGq2I/AAAAAAAAAAM/26lLN4emb50/s1600/base.png>
>
> In my pygame code I use to write this to let it scrolls smoothly in the
> background:
>
>
> base_shift = self.graphic.IMAGES['base'].get_width() -
> self.COMMON_CONST['screenWidth']
> while True:
> base_x = -((-base_x + 3) % base_shift)
> self.screen.blit(self.graphic.IMAGES['base'], (base_x, y))
>
> Basically the image is longer than the actual screen and once it passes
> the delta value between image X and screen X, the image is set to 0 again.
>
>
> I'm trying to do the same in pyglet inside the *def update(self, dt):*
> function but I have no idea exactly how to do it.
>
> I mean I understand the meaning of dt but still I can't get it.
>
> To move the image now I do something like this:
>
>
> def update(self, dt):
> self.base.x -= 30 * dt
>
> Of course this will continue to move and it does not reset his position.
> How can I replicate the behavior that I have done in pygame?
>
> I'm sorry maybe this is a stupid question, I'm a newbie trying to learn.
>
>
> thanks a lot
>
>
>
>
>
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