Hi, What about saving your resources by another name?
from pygr import metabase mdb = metabase.Metabase('.') test_genome = mdb('Bio.Seq.Genome.test_genome') mdb.add_resource('Bio.Seq.Genome.real_genome', test_genome) mdb.commit() On Wed, Jan 6, 2010 at 3:09 PM, Rochak Neupane <roc...@gmail.com> wrote: > Hi, > Is there a way I can create a resource that simply points to another > resource in the same DataPath? > > I'd like to create say: Bio.Seq.Genome.test_genome > and create Bio.Seq.Genome.real_genome which, if requested, simply > gives back Bio.Seq.Genome.test_genome > > Thanks! > > > -- > You received this message because you are subscribed to the Google Groups > "pygr-dev" group. > To post to this group, send email to pygr-...@googlegroups.com. > To unsubscribe from this group, send email to > pygr-dev+unsubscr...@googlegroups.com<pygr-dev%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/pygr-dev?hl=en. > > > >--
You received this message because you are subscribed to the Google Groups "pygr-dev" group.
To post to this group, send email to pygr-...@googlegroups.com.
To unsubscribe from this group, send email to pygr-dev+unsubscr...@googlegroups.com.
For more options, visit this group at http://groups.google.com/group/pygr-dev?hl=en.