On Wed, 2005-09-14 at 12:21 -0400, Mystilleef wrote:
> =====================================================
>
> import gtk
> from gnome import url_show
>
> gtk.about_dialog_set_url_hook(url_show, "http://www.google.com";)
>
> def create_about_dialog():
>
> dialog = gtk.AboutDialog()
> dialog.set_website_label("http://www.google.com";)
> dialog.show_all()
>
> return dialog
>
> =====================================================
>
> When I click on the link on the dialog, I get the following
> error:
>
> TypeError: url_show() takes exactly 1 argument (3 given)
>
>
> As you can see, I have passed exactly one argument to
> url_show. What am I doing wrong?
url_show takes 1 argument, but the callback from
about_dialog_set_url_hook should take 3. Thus, 3 args are being fed to
url_hook, which only takes one. Thus, your error message.
Working version:
=====================================================
#!/usr/bin/env python
import gtk
from gnome import url_show
dialog = gtk.AboutDialog()
def foo(dialog, arg2, arg3):
print dialog
print arg2
print arg3
#url_show(arg2)
gtk.about_dialog_set_url_hook(foo, "arg3")
dialog.set_website("arg2")
dialog.set_website_label("http://www.google.com";)
dialog.show_all()
gtk.main()
=====================================================
Or, since arg3 is optional, you can do something like
=====================================================
gtk.about_dialog_set_url_hook(lambda dialog, url: url_show(url))
dialog.set_website("http://www.google.com";)
dialog.set_website_label("http://www.google.com";)
=====================================================
Nigel.
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