At 2:23 PM +0100 2/15/06, =?iso-8859-2?Q?Jarek_Zgoda?= wrote:
>> Attached is your code changed so that it works.
>>=20
>> A diff between yours and mine should show you were you are going wrong.
>
>So, effectively you can not connect to signal not knowing its source (emi=
>tter)? I mean, in GTK you can not broadcast signal?

Correct.  The name "signal" is rather misleading, IMO.  Signals are just
lists of callbacks used for notification.
____________________________________________________________________
TonyN.:'                       <mailto:[EMAIL PROTECTED]>
      '                              <http://www.georgeanelson.com/>
_______________________________________________
pygtk mailing list   [email protected]
http://www.daa.com.au/mailman/listinfo/pygtk
Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/

Reply via email to