Rodrigo Renie Braga wrote:
ok, i'm doing some tests here with Numeric, and it seems that the
gtk.gdk.Pixbuf.get_pixels_array() returns an (Numeric) array with the
following shape: (w, h, 3), meaning a matrix with a dimension of WxHx3 ...
so, to access the rgb of a pixel on position (X, Y), i just use:
matrix[x][y][0] for red
matrix[x][y][1] for green
matrix[x][y][2] for blue
The correct indices are actually:
matrix[y][x][0] for red
matrix[y][x][1] for green
matrix[y][x][2] for blue
Think of the matrix as a sequence of rows, where each row is a sequence
of pixels, and each pixel is a 3-element vector of RGB (or 4-element RGBA).
is that right? And what is the best way to go through this matrix? maybe:
for i in matrix:
for j in i:
j[0] = color_red
j[1] = color_green
j[2] = color_blue
is this interaction changing the value of matrix? ( I don't lide the
looks of this loop.. :-) )
This will work; I'd just recommend using descriptive variable names to
make it more obvious:
for row in matrix:
for pixel in row:
pixel[0] = color_red
pixel[1] = color_green
pixel[2] = color_blue
--
Tim Evans
Applied Research Associates NZ
http://www.aranz.co.nz/
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