Have a look at this: http://fuhm.net/super-harmful/
;) On Fri, May 22, 2009 at 3:21 PM, Neil Dugan <[email protected]>wrote: > Christian Becke wrote: > > Jeffrey Finkelstein schrieb: > >> I'm new to Gtk. I tried to create a subclass of an HBox and add it to a > >> window, but I get a GtkWarning telling me that the assertion > >> `GTK_IS_WIDGET()' fails on the instance of my subclass. > >> > >> For example: > >> > >> ===code=== > >> > >> from gtk import Window, HBox, WINDOW_TOPLEVEL, main > >> > >> class FooBox(HBox): > >> def __init__(self): pass > > > > I think you have to call the constructor of the parent object here: > > def __init__(self): > > HBox.__init__(self) > > wouldn't it be better to use > super(FooBox,self).__init__() > > > and you have to make your new widget known: > > import gobject > > gobject.type_register (FooBox) > > > >> window = Window(WINDOW_TOPLEVEL) > >> window.add(FooBox()) > >> window.show_all() > >> main() > >> > >> ===/code=== > >> > >> yields a warning at "window.add()", namely "GtkWarning: > >> gtk_container_add: assertion `GTK_IS_WIDGET (widget)' failed". This > >> causes the widget to not be displayed in the window. > >> > >> I don't really understand why this is; am I missing a method call? > > > > Have a look at the gobject tutorial [1]. > > > > HTH, > > > > Chris > > > > [1] > > > http://www.sicem.biz/personal/lgs/docs/gobject-python/gobject-tutorial.html > > _______________________________________________ > > pygtk mailing list [email protected] > > http://www.daa.com.au/mailman/listinfo/pygtk > > Read the PyGTK FAQ: http://faq.pygtk.org/ > > > > _______________________________________________ > pygtk mailing list [email protected] > http://www.daa.com.au/mailman/listinfo/pygtk > Read the PyGTK FAQ: http://faq.pygtk.org/ >
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