#!/usr/bin/env python
import gtk
class Dialog:
def __init__(self):
dialog = gtk.Dialog("Dialog Example", None, 0,
(gtk.STOCK_CANCEL, gtk.RESPONSE_CANCEL, gtk.STOCK_OK, gtk.RESPONSE_OK))
dialog.set_default_size(250, 300)
label = gtk.Entry()
buttonbox = dialog.get_action_area()
buttons = buttonbox.get_children()
dialog.set_focus(buttons[0])
dialog.vbox.pack_start(label, True, True, 0)
dialog.show_all()
response = dialog.run()
if response == gtk.RESPONSE_OK:
print "OK"
elif response == gtk.RESPONSE_CANCEL:
print "CANCEL"
dialog.destroy()
Dialog()
The above is the easiest and quickest way I can think of. Essentially, you
access the ButtonBox which holds the buttons specified when constructing the
Dialog and retrieve the Button. This allows you to set the focus before the
Dialog is shown.
I have a feeling there is a better way, though it's not obvious to me at the
moment.
On Thu, 17 Nov 2011 12:42:36 -0300
craf <[email protected]> wrote:
> Hi.
>
> Is there any way to the OK button, keep the focus to start the program,
> and not the entry control?
>
> Here Code:---------------------------------
>
> #!/usr/bin/env python
>
> import gtk
>
> class Dialog:
> def __init__(self):
> dialog = gtk.Dialog("Dialog Example", None, 0,
> (gtk.STOCK_CANCEL, gtk.RESPONSE_CANCEL, gtk.STOCK_OK, gtk.RESPONSE_OK))
> dialog.set_default_size(250, 300)
> label = gtk.Entry()
>
> dialog.vbox.pack_start(label, True, True, 0)
> dialog.show_all()
>
> response = dialog.run()
>
> if response == gtk.RESPONSE_OK:
> print "OK"
> elif response == gtk.RESPONSE_CANCEL:
> print "CANCEL"
>
> dialog.destroy()
>
> Dialog()
>
>
> Thanks in advance!
>
> Regards.
>
> CRAF
>
> _______________________________________________
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> Read the PyGTK FAQ: http://faq.pygtk.org/
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